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3 years ago

12

Mrs. Dimitry purchased fish for dinner. She bought 6 pounds of fish for her party. If each person will eat 1/3 of a pound, how m

any people can she serve

1 answer:

PtichkaEL [24]3 years ago

3 0

18
1/3+1/3+1/3=1 pound
everyone gets 1/3

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What is the equation of the oblique asymptote?<br> h(x) = x² – 3x - 4/x + 2

NNADVOKAT [17]

Simplifying h(x) gives

h(x) = (x² - 3x - 4) / (x + 2)

h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)

h(x) = ((x + 2)² - 7x - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)

h(x) = (x + 2) - 7 - 22/(x + 2)

h(x) = x - 5 - 22/(x + 2)

An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

$\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0$

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.

4 0

2 years ago

The random variable X~(30,2^2) <br> Find p(X<33) <br> Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-30}{2} = 1.5$ >0

P(X<33) = P( Z<1.5)

= 1- P(Z>1.5)

= 1 - ( 0.5 - A(1.5))

= 0.5 + 0.4232

P(X<33) = 0.9232

<u>Step(iii) :-</u>

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-26}{2} = 3.5$ >0

P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

= 0.5 - 0.4990

= 0.001

P(X>26) = 0.001

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3 years ago

A rectangle has a width of 10 feet and a length of 40 feet. What is the length of the side of a square with the same area?

never [62]

First find the area of the rectangle: 10 * 40 = 400

Now, since the square has the same area, we'll find the side lengths of the square by just finding the square root of 400 which is 20. You can do this with a calculator. So the side length of any side on the square is 20.

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3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

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3 years ago

Mixed Applications

Orlov [11]

The solution to the given question will be:-

A) If a number, n, divided by 8 equals 2.5, what is n: n = 20

B) The sum of a number, n, and 6.05 is 12.4. What is n: n = 6.35

C) Stacy is one-fourth as old as her mother. If Stacy's mother is

36, how old is Stacy: 9 years

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

A) If a number, n, divided by 8 equals 2.5, what is n?

n / 8 = 2.5

n = 8 x 2.5 = 20

B) The sum of a number, n, and 6.05 is 12.4. What is n?

n + 6.05 = 12.4

n = 12.4 - 6.05 = 6.35

C) Stacy is one-fourth as old as her mother. If Stacy's mother is

36, how old is Stacy?

(1 / 4) M $_{age}$ = S $_{age}$

S $_{age}$ = ( 36 / 4)

S $_{age}$ = 9 years

Therfore the answers are n = 20 ,n = 6.35, S $_{age}$ = 9 years

To know more about Expression follow

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6 0

2 years ago