Answer:
Step-by-step explanation:
Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,
X is N(10, 6)
Or z = ![\frac{x-10}{6}](https://tex.z-dn.net/?f=%5Cfrac%7Bx-10%7D%7B6%7D)
is N(0,1)
a) P(X > 5),
=![P(Z>-0.8333)\\=0.7977](https://tex.z-dn.net/?f=P%28Z%3E-0.8333%29%5C%5C%3D0.7977)
(b) P(4 < X < 16),
=![P(|z|](https://tex.z-dn.net/?f=P%28%7Cz%7C%3C1%29%5C%5C%3D0.6826)
(c) P(X < 8),
=![P(Z](https://tex.z-dn.net/?f=P%28Z%3C-0.67%29%5C%5C%3D%200.2525)
(d) P(X < 20),
=![P(Z](https://tex.z-dn.net/?f=P%28Z%3C1.6667%29%5C%5C%3D%200.9522)
(e) P(X > 16).
=P(Z>-0.6667)
= 0.2524
Answer:
As consequence of the Taylor theorem with integral remainder we have that
![f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt](https://tex.z-dn.net/?f=f%28x%29%20%3D%20f%28a%29%20%2B%20f%27%28a%29%28x-a%29%20%2B%20%5Cfrac%7Bf%27%27%28a%29%7D%7B2%21%7D%28x-a%29%5E2%20%2B%20%5Ccdots%20%2B%20%5Cfrac%7Bf%5E%7B%28n%29%7D%28a%29%7D%7Bn%21%7D%28x-a%29%5En%20%2B%20%5Cint%5Ea_x%20f%5E%7B%28n%2B1%29%7D%28t%29%5Cfrac%7B%28x-t%29%5En%7D%7Bn%21%7Ddt)
If we ask that
has continuous
th derivative we can apply the mean value theorem for integrals. Then, there exists
between
and
such that
![\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x](https://tex.z-dn.net/?f=%20%5Cint%5Ea_x%20f%5E%7B%28n%2B1%29%7D%28t%29%5Cfrac%7B%28x-t%29%5Ek%7D%7Bn%21%7Ddt%20%3D%20%5Cfrac%7Bf%5E%7B%28n%2B1%29%7D%28c%29%7D%7Bn%21%7D%20%5Cint%5Ea_x%20%28x-t%29%5En%20d%20t%20%3D%20%5Cfrac%7Bf%5E%7B%28n%2B1%29%7D%28c%29%7D%7Bn%21%7D%20%5Cfrac%7B%28x-t%29%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%5CBig%7C_a%5Ex)
Hence,
![\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .](https://tex.z-dn.net/?f=%20%5Cint%5Ea_x%20f%5E%7B%28n%2B1%29%7D%28t%29%5Cfrac%7B%28x-t%29%5Ek%7D%7Bn%21%7Dd%20t%20%3D%20%5Cfrac%7Bf%5E%7B%28n%2B1%29%7D%28c%29%7D%7Bn%21%7D%20%5Cfrac%7B%28x-t%29%5E%7B%28n%2B1%29%7D%7D%7Bn%2B1%7D%20%3D%20%5Cfrac%7Bf%5E%7B%28n%2B1%29%7D%28c%29%7D%7B%28n%2B1%29%21%7D%28x-a%29%5E%7Bn%2B1%7D%20.)
Thus,
![\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}](https://tex.z-dn.net/?f=%20%5Cint%5Ea_x%20f%5E%7B%28n%2B1%29%7D%28t%29%5Cfrac%7B%28x-t%29%5Ek%7D%7Bn%21%7Dd%20t%20%3D%20%5Cfrac%7Bf%5E%7B%28n%2B1%29%7D%28c%29%7D%7B%28n%2B1%29%21%7D%28x-a%29%5E%7Bn%2B1%7D%20)
and the Taylor theorem with Lagrange remainder is
.
Step-by-step explanation:
One way would be to convert 40% into a fraction and multiply.
40% = 2/5
2/5 * 60 = 24
Drawing a diagram could involve drawing a whole (etc. a circle) and dividing it into fifths, then shading 2 of it with each section representing 12. Hope this helps!<span />
Answer:
1. X= 56
2. X= -11/2 (When you solve you get this if you need it as a mixed number it's X= -5 1/2
Step-by-step explanation:
simplifying means: Reducing to lowest terms.
To solve for x simplify both sides of the equation, then isolate the variable.