Using the given info, we can determine that
![(3(0) + 8) \div (2(0) - a) = - 2](https://tex.z-dn.net/?f=%283%280%29%20%2B%208%29%20%5Cdiv%20%282%280%29%20-%20a%29%20%3D%20%20-%202)
simplify
![8 \div - a = - 2](https://tex.z-dn.net/?f=8%20%20%5Cdiv%20%20-%20a%20%3D%20%20-%202)
multiply both sides by -a
and divide each side by -2
![4 = a](https://tex.z-dn.net/?f=4%20%3D%20a)
A = 4
Answer:
general solution=
+5
Step-by-step explanation:
using linear differential equation method
y'' + y' + y = 5
writing down the characteristics equation.
![m^2+m+1=0](https://tex.z-dn.net/?f=m%5E2%2Bm%2B1%3D0)
using quadratic formula
![m=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
we get
![m=\frac{-1\pm \sqrt{1^2-4(1)(1)}}{2(1)}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-1%5Cpm%20%5Csqrt%7B1%5E2-4%281%29%281%29%7D%7D%7B2%281%29%7D)
![m=-\frac{1}{2} \pm \frac{3}{2} i](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cpm%20%5Cfrac%7B3%7D%7B2%7D%20i)
now Complementary function(CF)
![y=e^{ax}(Acosbx+Bsinbx)\\y=e^{-\frac{1}{2} x}(Acos\frac{3}{2} x+Bsin\frac{3}{2}x)](https://tex.z-dn.net/?f=y%3De%5E%7Bax%7D%28Acosbx%2BBsinbx%29%5C%5Cy%3De%5E%7B-%5Cfrac%7B1%7D%7B2%7D%20x%7D%28Acos%5Cfrac%7B3%7D%7B2%7D%20x%2BBsin%5Cfrac%7B3%7D%7B2%7Dx%29)
now for particular integrals
![D^2y+Dy+y=5\\(D^2+D+1)y=5\\y=\frac{5}{D^2+D+1}](https://tex.z-dn.net/?f=D%5E2y%2BDy%2By%3D5%5C%5C%28D%5E2%2BD%2B1%29y%3D5%5C%5Cy%3D%5Cfrac%7B5%7D%7BD%5E2%2BD%2B1%7D)
![P.I.=\frac{5\times e^{0x} }{D^2+D+1}](https://tex.z-dn.net/?f=P.I.%3D%5Cfrac%7B5%5Ctimes%20e%5E%7B0x%7D%20%7D%7BD%5E2%2BD%2B1%7D)
putting D=0
we get
P.I.=5
general solution=CF+PI
general solution=
+5
One battery costs $1.44.
The unit rate would be
![\frac{1.44}{1 battery}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1.44%7D%7B1%20battery%7D%20)
To get that answer, you would have to divide 13 ÷ 9.
I'm not sure if this is what you were looking for, but if it was, I hope I helped! :-)
Answer:
(2x)^3+(y)^3=(2x+y)(4x^2-2xy+y^2)
Step-by-step explanation:
a= 2x and b = y
then a^3 + b^3 = ?
We know that:
a^3+b^3 = (a + b)(a^2 – ab + b^2)
Putting a =2x and b=y and finding the answer
(2x)^3+(y)^3=(2x+y)((2x)^2-(2x)(y)+(y)^2)
(2x)^3+(y)^3=(2x+y)(4x^2-2xy+y^2)
So, (2x)^3+(y)^3=(2x+y)(4x^2-2xy+y^2)
B) ABCD is a rhombus as all the sides are congruent (equal)