Last Question plz Need help

Mathematics

1 answer:

patriot [66]3 years ago

5 0

Answer:

Im going to answer your question in the next note.

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After riding a bike 9 miles,Alex’s total time was 40 1/2 minutes. Find his time per mile.

r-ruslan [8.4K]

40.5/9= 4.5 minutes per mile.

5 0

2 years ago

25 students are learning how to make balloon animals. There are 194 balloons to be shared equally among the students. How many b

alexdok [17]

25 students
194 balloons

194/25 = 7.76
Each student gets 7 balloons, 7 x 25 = 175 balloons will be used
194 - 175 = 19 balloons remaining (Answer to part 1 of this question)

If each student needs 8 balloons
8 * 25 = 200
200 - 194 = 6 ballons needed (Answer to part 2 of this question)

We also could have found the answer to part 2 by saying that we had 19 balloons left over when the students each were given 7 balloons
Each student needs another 1 balloon = 25 balloons,
We have 19 left over
25 - 19 = 6 balloons need to be purchased (we got the same answer both ways so it is very likely we have the correct answer)

6 0

3 years ago

If K is the midpoint of JL, JK = 8x+11 and KL = 14x-1, find JL.

gladu [14]

Step-by-step explanation:

Since, K is the midpoint of JL.

$\therefore \: JK = KL \\ 8x + 11 = 14x - 1 \\ 11 + 1 = 14x - 8x \\ 12 = 6x \\ \frac{12}{6} = x \\ 2 = x \\ \\ \because \: JL = JK + KL \\ \therefore \: JL = 8x + 11 + 14x - 1 \\ \therefore \: JL = 8x + 14x + 11 - 1 \\ \therefore \: JL = 22x + 10\\ \therefore \: JL = 22 \times 2 + 10..(plug \: x = 2) \\ \therefore \:JL = 44 + 10 \\ \huge \red{ \boxed{\therefore \:JL = 54}}$

7 0

3 years ago

Read 2 more answers

A small appliance is regularly priced at $60. On sale

Vlad [161]

The selling price would be 30$ how I got was a divided 20 by 60 and so 20 goes into 60 3times that’s how I got 30$

4 0

3 years ago

PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

7 0

3 years ago