Answer:
the actual pressure is 31.09
Complete question:
What is the actual pressure when Ali's gauge shows 33.58
Step-by-step explanation:
Given,
Ali's tyre presser gauge show a reading 8% higher than the actual pressure.
Ali's gauge shows 33.58.
Let the actual pressure be x.
According to problem,
{ [If 8% increasing of a no ⇒ The number becomes = 
of the number}
x= 
x=31.09
Therefore, the actual pressure is 31.09
Answer:
......
Step-by-step explanation:
55
Make this brainliest please, and thank you
Answer:
P<em>=52in is ya answer!</em>
Answer:
242 cm
Step-by-step explanation:
1. Find the scale factor
A scale factor (SF) is the ratio of two corresponding lengths in similar figures.
SF = actual distance/scale distance
If the scale width is 3.8 cm,
SF = 418 cm/3.8 cm = 110
2. Calculate the actual depth
110 = actual depth/2.2 cm
Actual depth = 110 × 2.2 cm = 242 cm
We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56
