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3 years ago

Find the quotient: (x2−5x+8)÷(x+2)

Mathematics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

Quotient = x - 7

Step-by-step explanation:

We are dividing x^2 - 5x +8 by x + 2

x + 2√x^2 - 5x + 8

Starting with dividing by x

x - 7

x + 2√ x^2 - 5x + 8

Multiplying x by x + 2

x + 2√ x^2 - 5x + 8

x^2 + 2x

= -7x + 8

Step ii, pick -7 for division

-7x + 8

-7x - 14

= +8 -(-14)

= 8+14

= 22

The answer is

( x - 7) remainder 22

(x - 7) is the quointent

22 is the remainder

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The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

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Step-by-step explanation:

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writing in the slope-intercept form

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now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

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substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

$\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)$

$y+2=\frac{3}{4}\left(x+4\right)$

Thus, the equation in the point-slope form of the line equation is:

$y+2=\frac{3}{4}\left(x+4\right)$

Simplifying the equation

$y+2=\frac{3}{4}\left(x+4\right)$

Subtract 3 from both sides

$y+2-2=\frac{3}{4}\left(x+4\right)-2$

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Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

$y+2=\frac{3}{4}\left(x+4\right)$

$3x - 4y = -4$

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