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Dmitry_Shevchenko [17]
3 years ago
6

A certain intelligence test has an N(100, 100) distribution. To see whether intelligence is inherited, tests are given to the el

dest child of each of a random sample of 16 acclaimed scholars. The average score of the children is 105. a. Give the null hypothesis to be tested. b. Give the alternative hypothesis. c. Perform the test. d. How likely is it that data like these represent a sample from a population in which the null hypothesis is true?
Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

Follows are the solution to the given choices:

Step-by-step explanation:

In choice a:

\to \mu = 100

In choice b:

\to \mu \neq 100

In choice c:

\to \ pop  \ average=100 \\\\ \to \ variance \ of \ pop = 100  \\\\\to pop  \ \  \sigma = \sqrt {(!00)} \\

               = 10

z= \frac{\bar x - \mu}{ \frac{\sigma}{\sqrt(n)}}\\\\

   =\frac{(105-100)}{\frac{10}{ \sqrt(16)}}\\\\=\frac{(5)}{ \frac{10}{4}}\\\\=\frac{5}{ \frac{5}{2}}\\\\= \frac{10}{5}\\\\=2

\to p==2\times (1- \ righttail)\\\\\to \ righttail\ \ p = \text{NORM.S.DIST(2,TRUE)}

                        =0.977249868

\therefore \\P=2 \times (1-0.9772)\\\\P=0.0455\\\\P

Null hypothesis to dismiss  

Alternate solution assumptions embrace  

There is really no valid proof at the 5% stage that  

Knowledge is legacy

In choice d:

Possibly information such as this reflect a sample population with such a true p = 0.0455 meaning in the hypothesis  

u is around 100.  

11 +001

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shusha [124]

Answer:

x = -3

Step-by-step explanation:

y\geq -\frac{2}{3} x-3\\
y\leq 3x+8

-\frac{2}{3} x-3=3x+8

Add 2/3 x to both sides:  -3=\frac{11}{3}x+8

Subtract 8 from both sides: -11=\frac{11}{3}x

Multiply both sides by 3:  -33=11x

Divide both sides by 11:  x=-3

Therefore, point of intersection between both lines is at point (-3, -1)

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2 years ago
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2 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

8 0
3 years ago
I need to know how to do this step my step and the answer
MissTica
You can use the calculator or 0^2 is 0 x -3 =0 +7 (0) -4 =-4
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3 years ago
Solve the following function for y when x=5 round to the nearest tenth
Wittaler [7]

In the given question , we have a function given , which is

y= 13(0.5^x)

And we need to find the value of y when x=5.

So we substitute 5 for x and solve for y, that is

y=13(0.5^5) = 0.40625

And on rounding to the nearest tenths, we will get

y=0.4

So when x=5, y=0.4

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3 years ago
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