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Zepler [3.9K]
3 years ago
5

Simplify 2.8d-6+3.8-3.1d

Mathematics
1 answer:
densk [106]3 years ago
6 0

Answer:

-0.3d-2.2

Step-by-step explanation:

2.8d-6+3.8-3.1d

Combine like terms

2.8d-3.1d   -6+3.8

-0.3d-2.2

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Silva set up a dog-walking business. He earned $60 in June. He is projected to earn 110% more in July. How much is Silva project
MissTica

Answer:

$126

Step-by-step explanation:

just used the calculator

4 0
2 years ago
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If the diameter of a cylinder is 18 inches, the radius of the cylinder is 9 inches.
Afina-wow [57]

Answer:

True

Step-by-step explanation:

A cylinder has two circles as its bases, and the diameter formula is:

2r = d

So if you plug in:

2r = 18

---    ---

2     2

r = 9

So it will be true.

Hope this helped.

7 0
3 years ago
Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x
Mrac [35]

Answer:

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

Step-by-step explanation:

The given functions are f(x)=\frac{3x-1}{x-4} and g(x)=\frac{x+1}{x} .

We now composed the two functions to find:

(f\circ g)(x)=f(g(x))

\implies (f\circ g)(x)=f(\frac{x+1}{x})

\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}

\implies (f\circ g)(x)=\frac{4x+3}{1-3x}

This function is defined if the denominator is not zero.

1-3x\ne0

x\ne\frac{1}{3}

We write this in interval notation as:

(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of (f\circ g)(x) is

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

4 0
3 years ago
A + (-5) = 12<br><br> a) a= -17<br> b) a = -7<br> c) a = 7<br> d) a = 17
bazaltina [42]
D) is the answer ......
5 0
3 years ago
What is the additive inverse of 3?<br> a. -3<br> b. a+(-a)=0<br> c. 0<br> d. -a
finlep [7]

Answer:

<em>A. -3</em>

Step-by-step explanation:

<em>3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.</em>

8 0
2 years ago
Read 2 more answers
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