Answer:
Distance formula is below
Step-by-step explanation:
15^2 + 20^2
= 225 + 400
= 625
square root of 625 = 25
answer:<span>length of the Hypotenuse is</span> 25
The answer of this is x=0

Notice that

So as

you have

. Clearly

must converge.
The second sequence requires a bit more work.

The monotone convergence theorem will help here; if we can show that the sequence is monotonic and bounded, then

will converge.
Monotonicity is often easier to establish IMO. You can do so by induction. When

, you have

Assume

, i.e. that

. Then for

, you have

which suggests that for all

, you have

, so the sequence is increasing monotonically.
Next, based on the fact that both

and

, a reasonable guess for an upper bound may be 2. Let's convince ourselves that this is the case first by example, then by proof.
We have


and so on. We're getting an inkling that the explicit closed form for the sequence may be

, but that's not what's asked for here. At any rate, it appears reasonable that the exponent will steadily approach 1. Let's prove this.
Clearly,

. Let's assume this is the case for

, i.e. that

. Now for

, we have

and so by induction, it follows that

for all

.
Therefore the second sequence must also converge (to 2).
The area of the trapezoid is x+11 cm.
Given a trapezoid has one side of (x+6) cm, the other side is 5 cm, and the height is 2 cm.
A two-dimensional quadrilateral consisting of the sum of non-adjacent parallel sides and a suitable non-parallel side is denoted as a trapezoid.
Now we will use the formula to find the area of a trapezoid
Area = 1/2 × (base 1 + base 2) × height
Here base 1 = (x+6) cm, base 2 = 5cm and height = 2cm
Substituting the values into the formula, we get
Area = 1/2 × (x+6+5) × 2
Area = 1/2 × (x+11) × 2
Area = x+11
Thus, the area of the given figure when one side is x+6, the other side is 5 cm and the height is 2 cm is x+11 cm.
Learn more about the area of trapezium from here brainly.com/question/15815316
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