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3 years ago

12. The $60 selling price of a camera is the cost

Mathematics

1 answer:

lbvjy [14]3 years ago

3 0

Answer:

I can help but your question does not make sense. You said the price of the camera is $60 and the question is find the cost?

Step-by-step explanation:

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PLease tell me the inequalities and the answers also label which problems you d. I was out sick and I have no idea what to do lo

tatuchka [14]

Answer:

1) Amy can invite 17 people.

2) x > 76

3) 40 - 6 is greater than or equal to 3x

4) x is greater than or equal to 98

Step-by-step explanation:

1) 50 + 8x = 200

2) 200 < 3x - 28

3) 40 = 6 +3x

4) (95 + 78 + 89 + x)/4 is greater than or equal to 90

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2 years ago

5 times 3 and 5 over 8 times 9 and 1 over 4

Ber [7]

The answer should be:
20.875

Hope this helps.

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3 years ago

Read 2 more answers

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

3 years ago

If (20, 14) is an ordered pair of the inverse of F(x), which of the following is an

Law Incorporation [45]

Answer:

A. (14,20)

Step-by-step explanation:

The inverse relation is found by swapping x and y in the ordered pair.

When ...

14 = f^-1(20)

then ...

20 = f(14)

The corresponding ordered pair is (14, 20).

3 0

3 years ago

What should be added to (-5 a2b - 9 ab) to get a2b + 3 ab?

Doss [256]

Based on given conditions,

$a²b + 3 ab - (-5 a²b - 9 ab)$

$→a²b + 3 ab + 5 a²b + 9 ab$

$→(a²b + 5 a²b) + (3ab + 9 ab$

Now collecting the coefficients and adding them,

$(1 + 5)a²b + (3 + 9)ab$

$→6 {a}^{2}b + 12ab$

Hence, the 6a²b + 12ab should be added.

5 0

2 years ago