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olchik [2.2K]
3 years ago
11

two runners are competing in a race. one runner averages a pace of 7 minutes per mile and finishes the race in 28 minutes. the s

econd runner finishes the race in 30 minutes. which of the following is the pace of the second runner?
Mathematics
1 answer:
stealth61 [152]3 years ago
8 0
7minutes and 30 seconds
28/7=miles mile*30=second runners pace
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Answer:

  140°

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Angles 1 and 3 are "corresponding" angles, so are congruent.

  ∠1 = ∠3

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  40 = 10x . . . . . . . . . . . . subtract 20x+20

  4 = x . . . . . . . . . . . . . . divide by 10

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2 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

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We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

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3 years ago
Write without the absolute value sign. |x-3| if x>4
lisabon 2012 [21]
If x>4, then the quantity x-3 inside the absolute value symbol is already positive.  So, in this case, |x-3|  =>  x-3, and   x-3 is all you need to write.
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