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Darya [45]
3 years ago
12

0.4(2x + 0.3) = 1/3 (6x - 7.2)

Mathematics
2 answers:
GenaCL600 [577]3 years ago
5 0
What are u looking for ?
Hitman42 [59]3 years ago
4 0

Answer:

x = 20.1

Step-by-step explanation:

First up you need to multipy the numbers on the outside with the ones on the inside

This would mean that

0.4(2x + 0.3) = 1/3(6x  - 7.2) will change to

0.8x + 0.12 = 2x - 2.4

You just have to solve for x now:

2.4 + 0.12 = 2x - 0.8x

2.52 = 1.2x

x = 2.1

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Which of the following are solutions to the equation below?
lana66690 [7]

Answer:

F. - 4

Hope it help

8 0
3 years ago
How would I solve the equations: y = x-4 and y=x^2-4x using substitution
andriy [413]

Answer:

x = 6

Explanation:

y = x - 4

26 = 4x + y


If y = y, then we can rewrite this system as this: 4x + x - 4 = 26


Then we combine like terms and add 4  on both sides to give us  5  x  =  30 . Divide by 5 on both sides and we arrive at the solution: x = 6

6 0
3 years ago
Anybody wanna c h at zoo m<br> 928-1137-7133<br> HtHq72
docker41 [41]
Nahh
Explanation: noooo
5 0
3 years ago
Read 2 more answers
Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i
aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175

Positive when there is raritanium:

98% of 13%

P(A) = 0.98*0.13 = 0.1274

What is the probability the rock sample actually contains raritanium?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0
2 years ago
Find two matrices A and B such that 2A-3B= [5 0
amm1812

The easy answer: If, say, B is the zero matrix, i.e.

B=\begin{bmatrix}0&0\\0&0\end{bmatrix}

then

2A=\begin{bmatrix}5&0\\-1&2\end{bmatrix}\implies A=\begin{bmatrix}\dfrac52&0\\\\-\dfrac12&1\end{bmatrix}

3 0
3 years ago
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