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3 years ago

I WILL MARK BRAINLIEST :]

Mathematics

1 answer:

Maurinko [17]3 years ago

6 0

Answer:

A. . A cheeseburger is $7.95 plus $1.00 for each additional topping.

Step-by-step explanation:

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Khloe and her children went into a grocery store and will buy peaches and mangos. She must buy a maximum of 7 peaches and mangos

PolarNik [594]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the minimum value of the following equation:

Mandarinka [93]

Answer:

×=11

Step-by-step explanation:

2×-4×+27-5=0

-2×+22=0

-2×=-22

×=11

8 0

2 years ago

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0

3 years ago

There are eight questions, worth ten points. How many points is each question worth?

Margarita [4]

Answer:

Step-by-step explanation:

8 questions worth 10 points...

10/8 = 1.25 points per question <==

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B8a%5E%7B-5%7Db%5E%7B4%7D%20%7D%7B12a%5E%7B-6%7Db%5E%7B-2%7D%20%7D%29" id="TexForm

Oxana [17]

Answer:

$→ \frac{8 {a}^{( - 5) } {b}^{(4)} }{12 {a}^{( - 6)} {b}^{( - 2)} } = \frac{2 {a}^{(6 - 5)}{b}^{(4 + 2)} }{3} = \boxed{ \frac{2}{3}a {b}^{6} }✓ \\$

<u>(2/3)ab⁶</u> is the right answer.

6 0

3 years ago