Bottom left. Because of th eminus sign, the v curve is "upside-down" and because of the +1, its function value peak is at 1
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
x = 14
< A = 58 degrees
< B = 52 degrees
< C = 70 degrees
Step-by-step explanation:
Recall that the addition of the three internal angles of a triangle must render 180 degrees, then we can write:
<A + <B + <C = 180
and now replace with the algebraic expressions given for each angle:
2(x + 15) + 3 x + 10 + 5 x = 180
eliminate parenthesis
2 x + 30 + 3 x + 10 + 5 x = 180
combine like terms
10 x + 40 = 180
subtract 40 from both sides
10 x = 140
divide both sides y 10 to isolate x
x = 14
Now that we know x, we can calculate each of the angles using the fiven expressions:
< A = 2 (x + 15) = 2 (14 + 15) = 2 * 29 = 58 degrees
< B = 3 x + 10 = 3 * 14 + 10 = 52 degrees
< C = 5 x = 5 * 14 = 70 degrees
The answer is $0.8
200/160=1.25
200+160=360/1.25/160=200.8
so the answer is $0.8
