Answer:
<u>The lengths of side A is 22.4 and B is 11.9</u>.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25 using the Pythagorean Theorem.
Now, to find the lengths of side A and B.
Let the side B be ![x.](https://tex.z-dn.net/?f=x.)
So, the side A be ![2x.](https://tex.z-dn.net/?f=2x.)
Side C = 25.
Now, to solve by using Pythagorean Theorem:
A² + B² = C²
![(2x)^2+(x)^2=(25)^2](https://tex.z-dn.net/?f=%282x%29%5E2%2B%28x%29%5E2%3D%2825%29%5E2)
![4x^2+x^2=625](https://tex.z-dn.net/?f=4x%5E2%2Bx%5E2%3D625)
![5x^2=625](https://tex.z-dn.net/?f=5x%5E2%3D625)
<em>Dividing both sides by 5 we get:</em>
![x^2=125](https://tex.z-dn.net/?f=x%5E2%3D125)
<em>Using square root on both sides we get:</em>
![x=11.18.](https://tex.z-dn.net/?f=x%3D11.18.)
<u>B rounding to the nearest tenth = 11.9.</u>
Now, to get A by substituting the value of
:
![2x\\=2\times 11.18\\=22.36.](https://tex.z-dn.net/?f=2x%5C%5C%3D2%5Ctimes%2011.18%5C%5C%3D22.36.)
<u>A rounding to the nearest tenth = 22.4.</u>
Therefore, the lengths of side A is 22.4 and B is 11.9.
I believe the correct question is:
6.7*10^7 calc/sec?
So:
1/(6.7 x 10^7) = seconds per calculation
1/(6.7 x 10^7) = 100/(6.7 x 10^9) = 14.9 x 10^-9 seconds per
calculation = 14.9 ns
Which is approximately 15 ns
Answer:
15 ns
Answer: 28
EXPLANATION:
16 ÷ 64 = 4
7 x 4 = 28
Answer:
Width=4, and Length=17
Step-by-step explanation:
first you will make a variable for the width which i will say is x
now make it an equation (3x+5) (x) = 68
then solve 3x^2+5x=68
then 3x^2+5x-68=0
then x=4
then you have to substitute so 3(4)+5= 17 and 4