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4 years ago

What is the value of y?

Mathematics

1 answer:

meriva4 years ago

7 0

Answer:

-2

Step-by-step explanation:

So if Y=2x then X = -2 + 6

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The grade seven students are showing a movie in their school auditorium to raise money for the end of year field trip. Goal is t

Andreas93 [3]

Answer:

The answer is A because it needs to be a filled dot to represent the information correctly. 16 x 20 is 320 so they need 180 more to have at least 500 dollars which is 11.25 tickets but you cant have a fourth of a ticket so you need atleast 12 tickets sold.

6 0

3 years ago

Abby and Annie have the same number of coins.

svetlana [45]

Answer:

2400 coins

Step-by-step explanation:

What we should do is calculate the Least Common Multiple of 80 and 75, since each of us put together a group with this amount of coins, this way we will know the amount of coins when they are equal.

To obtain the L.C.M

you have to factor both numbers and multiply the numbers whose exponent is the highest, it looks like this:

75 = 5 ^ 3

80 = 2 ^ 4 * 5

We multiply those with the highest exponent,

5 ^ 3 = 75

2 ^ 4 = 16

75 * 16 = 1200.

L.C.M. is 1200.

Since they tell us that they have less than 2000 coins, this is the correct answer, because when assembling these groups in this way, they coincide again in 2400, which is over the limit.

So, each one has 1200 coins, in total it would be:

1200 * 2 = 2400

Between them they have a total of 2400 coins

3 0

3 years ago

Drag each number to the box on the right so it matches the value of the expression on the left. Each number may be used once, mo

ladessa [460]

Answer:

[4*(4+3)]-3 = 25

[(7-5)-: 1/2]*2 = 8

((5.4+3)*(6-2)) = 33.6

(9)/(3)+6)*3 = 27

(4+3.2)*[(9-2)+2.5] = 68.4

Step-by-step explanation:

4 0

3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Which two points on the number line are opposites?

Afina-wow [57]

Answer:

B and C

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers