<span>You are given a roster with 3 guards, 5 forwards, 3 centers, and 2 "swing players" (x and y) who can play either guard or forward. You are given a condition that 5 of the 13 players are randomly selected. You are asked to find the probability that they constitute a legitimate starting lineup.
</span>For these cases, there are a lot so,
legitimate ways:
two swings and one gurad = 2C2*5C2*3C1 = 30
two swings used as forwards = 3C2*2C2*3C1 = 9
two swings used one guard = 2C1*3C1*1C1*5C1*3C1 = 90
one swing used as forward = 3C2*2C1*5C1*3C1 = 90
zero swing used = 3C2*5C2*3C1 = 90
total of legitimate ways = 489
Total ways = 13C5 = 1287
The probability that they constitute a legitimate lineup is = 489/128 = 0.38
Answer:
Step-by-step explanation:
hello
so the dimensions of the rectangle are
5a-6b and 5a+6b
hope this helps
Answer:
C≈31.42cm
Step-by-step explanation:
Solution
C=2πr=2·π·5≈31.41593cm
Then the probability is
P(a)+P(b)-P(a&b)
0.5+0.3-0.5*0.3=0.8-0.15=0.65
Answer: 8 hours
Step-by-step explanation:
<u>Given information</u>
Admission fee = $7.00
Hour rent fee = $1.50
Number of hours = h
Total fee = $19
<u>Set equation according to the given information</u>
Total fee = admission fee + (hours) × (hour rend fee)
<u>Substitute values into the equation</u>
19 = 7 + 1.5h
<u>Subtract 7 on both sides</u>
19 - 7 = 7 + 1.5h - 7
12 = 1.5h
<u>Divide 1.5 on both sides</u>
12 / 1.5 = 1.5h / 1.5
Hope this helps!! :)
Please let me know if you have any questions
