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Aleksandr [31]
3 years ago
15

When you compare the numbers on the left, you need to look at the ones digits. When you compare the numbers on the right, you do

not need to compare the ones digits. Explain. 5,278 5,272 5,398 5,353
Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

Same digits till the ones digits

Same digits till tens digits

Step-by-step explanation:

* Lets explain how to solve the problem

- The numbers on the left are 5,278 and 5,272

- When we compare any to numbers with the same number of digits

  we must start from the leftmost digit and go to the right

∵ The two numbers have 4 digits ⇒ thousands - hundreds - tens - one

∵ The leftmost digits in the 2 numbers (thousands) are equal

∵ The hundreds digits of the 2 number are equal

∵ The tens digits of the 2 number are equal

∴ We must to look at the ones digits to compare between them

∴ <u><em>We need to look at the ones digits</em></u>

- The numbers on the right are 5398 and 5353

∵ The two numbers have the thousands digits

∵ The two numbers have the same hundred digits

∵ The two numbers not having the same tens digits

∴ We compare between them using the tens digits not the

   ones digits

∴ <u><em>We do not need to compare the ones digits</em></u>

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The probability of getting a total of 8 when two dice are rolled is 0.139.

Probability is a number that expresses the likelihood or chance that a specific event will take place. Probabilities can be represented by proportions on a 0–1 scale.

A single die will have six sides with the numbers: 1, 2, 3, 4, 5, and 6. Each of these events is equally likely to occur if the dice are rolled fairly. So the probability of getting any side of the number is 1/6. Therefore, the probability of getting 1 in dice is 1/6, 2 is 1/6, and so on.

Therefore, the total possible outcomes are the multiplication of the total possible outcomes on dice 1 and dice 2, which is 36.

This possible outcome of rolling two dice is given by,

\left\{\begin{array}{ccccccc}(1, 1)&(1, 2)& (1, 3)&(1, 4)&(1, 5)&(1, 6)\\(2, 1)&(2, 2)&(2, 3)&(2, 4)&(2, 5)&(2, 6)\\(3, 1)&(3, 2)&(3, 3)&(3, 4)&(3, 5)&(3, 6)\\(4, 1)&(4, 2)&(4, 3)&(4, 4)&(4, 5)&(4, 6)\\(5, 1)&(5, 2)&(5, 3)&(5, 4)&(5, 5)&(5, 6)\\(6, 1)&(6, 2)&(6, 3)&(6, 4)&(6, 5)&(6, 6)\end{array}\right\}

The probability of getting a total of 8 from both dice is given by, (2, 6) (3, 5) (4, 4) (5, 3) (6, 2). So the number of favorable outcomes is 5 and the total outcome is 36. The probability is P(getting a total of 8 from both dices)=5/36= 0.139.

The answer is 0.139.

The complete question is -

Consider rolling dice and getting a total of 8. Find the probability of two dice are rolled. (Enter the value of probability in decimals. Round the answer to three decimal places).

To know more about dice probability:

brainly.com/question/17239706

#SPJ4

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Step-by-step explanation:

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