Answer:
i) 769 E. coli cells should be laid end to end would fit across a pinhead of diameter 0.5 mm.
ii) is the volume of an E. coli cell.
iii) The surface area of E coli cell is and surface area to volume ratio of an E. coli cell is .
Explanation:
Diameter of the Escherichia coli cell ,d= 2.85 μm = 0.00285 mm
1 μm = 0.001 mm
Length of the Escherichia coli cell ,h= 0.650 μm = 0.000650 mm
Let the number of Escherichia coli cell laid end to end to total length of 0.5 mm be x
769 E. coli cells should be laid end to end would fit across a pinhead of diameter 0.5 mm.
Radius of the Escherichia coli cell r = d/2 =
Length of the Escherichia coli cell ,h = 0.000650 mm
Volume of the cylinder =
Volume of the E coli cell: V
Total surface area of cylinder :
Area of the E coli cell: A
Surface area to volume ratio of an E. coli cell: