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Leno4ka [110]
3 years ago
13

What property is applied to simplify the expression (ab)ca =ab(ca)?

Mathematics
1 answer:
matrenka [14]3 years ago
8 0
Distributive property
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Srekar needs to increase the size of the prism below by 2 inches on each side. The original prism has a length of 3, a depth of
Leto [7]

Answer:

a b

Step-by-step explanation:

The options as obtained from the internet.

- the new prism will have a length of 5

- the new prism will have a depth of 4

- the new prism will have a height of 2

- the volume will increase by 6 and each of the 3 dimensions is increased by 2.

- srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

The volume of a rectangular prism is (length × depth × height)

Originally, length = 3 inches

Depth = 2 inches

Height = 1 inch

Original volume = 3×2×1 = 6 in³

Then, Sreka adds 2 inches to each of the dimensions,

New length = 3+2 = 5 inches

New depth = 2+2 = 4 inches

New height = 1+2 = 3 inches

New volume = (5×4×3) = 60 in³

Taking each of the statements one at a time

Statement 1

the new prism will have a length of 5

True!

Statement 2

the new prism will have a depth of 4

True!

Statement 3

the new prism will have a height of 2

False! New height = 3 inches

Statement 4

the volume will increase by 6 and each of the 3 dimensions is increased by 2.

This is false. The volume increased to 10 folds of its original volume.

Statement 5

srekar could increase the volume by the same amount by just adding 6 to the height instead of 2 to each side

Adding 6 inches to the height,

New height = 1+6 = 7 inches

New volume = 3×2×7 = 42 in³

This statement is false as the new volume from adding 2 inches to each side is 60 in³

Hope this Helps!!!

5 0
3 years ago
vanesa multiplies two integers. When she adds the product to 4, the sum is 0. What can you say about the two integers
Lelu [443]
The Integers Are Positive They Are Not Negative Numbers. If It Was Negative It Would Be -2,-3,-4. While If It's Positive It Should Be 0,1,2,3,4 And So On.
4 0
3 years ago
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
scoundrel [369]

Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

∆JKL is dilated by a scale factor = 2

Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

Tan(b°) = 3/4

Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.

Therefore, tan(b°) = three fourths (C)

6 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
HELP ASAPPPP!!!!You are making a picture frame in the craft cabin at summer camp. The frame measures 9 inches by 12
Greeley [361]

Answer:

yes

Step-by-step explanation:

euhm ... did u just asked if a figure with h=9inches and b=12inches is rectangular???

Does it matter what the diagonals are etc?

if the frame has angles of 90° and it has two different lengths then it has to be rectangular. The sides of a square would have the same lengths.

7 0
3 years ago
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