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Serggg [28]
3 years ago
10

Which one is it can someone help me please

Mathematics
2 answers:
mars1129 [50]3 years ago
7 0
The answer should they’re oone if the top left.
TiliK225 [7]3 years ago
5 0
The answer is the one on the left (top left)
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Is 11,13,17 a right triangle
11Alexandr11 [23.1K]

Answer:

no

Step-by-step explanation:

We can use the Pythagorean theorem to check

a^2 +b^2 = c^2

11^2+13^2 = 17^2

121+169 =289

410 does not equal 289

This is not a right triangle

3 0
3 years ago
Read 2 more answers
Least common denominator?
Over [174]

Answer:

\large\boxed{(s-2)(s+2)(s-3)=(s^2-4)(s-3)=s^3-3s^2-4s+12}

Step-by-step explanation:

s^2-4=s^2-2^2=(s-2)(s+2)\\\\\text{used}\ a^2-b^2=(a-b)(a+b)\\\\s^2-5s+6=s^2-2s-3s+6=s(s-2)-3(s-2)=(s-2)(s-3)\\\\\text{Therefore}\ LCD(s^2-4,\ s^2-5s+6)=(s-2)(s+2)(s-3)

4 0
3 years ago
Your field experience instructor wants to line up 8 cars for transportation. There are 27 cars available. How many different gro
ValentinkaMS [17]

Answer:

3

Step-by-step explanation:

8*3 is 24 and you cannot add another 8 after that

6 0
3 years ago
Which figures are polygons?
LenaWriter [7]
A B and D

A & D are known as irregular polygons
3 0
3 years ago
When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
3 years ago
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