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Leno4ka [110]
3 years ago
6

What’s the lowest term for 10/16

Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

<h2>5/8</h2>

Step-by-step explanation:

Divide each term of the fraction by <u>2</u>.

10 / 2 = 5

---------------------

16 / 2 = 8

It cannot be simplified lower than 5/8.

Therefore, 5/8 is your answer

Best of luck to you.

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Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.
liberstina [14]

Correct answer is A.

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

<h3>How to calculate the diameter?</h3>

If you know the radius of the circle, multiply by 2 to get the diameter. The radius is the distance from the center of the circle to the edge. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2 = 8 cm. If you know the circumference of the circle, divide by π to get the diameter.

<h3>Briefing:</h3>

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction which is A.

The diameter of the circle is used for the square as l=2r therefore corresponds to the diameter, while for a hexagon r=r being the radius of the circle.

To know more about Diameter visit:

brainly.com/question/5501950

#SPJ4

I understand that the question you are looking for is:

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

A) The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

B) The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

C) The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

D) The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

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1 year ago
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3 years ago
Can anybody solve this, it’s due soon
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