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QveST [7]
4 years ago
7

Alice and Dave left school at the same time walking in opposite directions. Alice walked at an average speed of 280 ft/min and D

ave walked at an average speed of 320 ft/min.
Mathematics
1 answer:
Svetach [21]4 years ago
3 0

Answer:

600 ft

Step-by-step explanation:

Alice's Average Speed=280 ft/min

Dave's Average Speed=320 ft/min.

Distance = Average Speed X Time

In 1 minute, their distances from their starting point is determined below.

Alice's Distance=280 X 1=280ft

Dave's Distance= 320 X 1=320ft

Since they walk in opposite direction, their distance from each other will be the sum of their distances from the starting point.

Distance of Alice from Dave=280+320=600 ft

In 1 minute, they were 600 ft apart.

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Aleks [24]

Answer:

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Step-by-step explanation:

A 45-45-90 traingle is a special traingle.  Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem.  Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2.  2(x)^2=c^2.  You then square root both sides and get c= x√2.  

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