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Setler79 [48]
3 years ago
10

Can someone also help me with this other diagram problem?

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0

Answer: the length of the other side is 16.5 units.

Step-by-step explanation:

The rectangle has 2 equal and parallel sides. Each of the 4 angles in a rectangle is 90°. This means that the diagonal of the rectangle divides it into 2 equal right angle triangles and the diagonal represents the hypotenuse of both right triangles.

To determine the length of the other side, x, we would apply Pythagoras theorem. It is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore

17² = x² + 4²

289 = x² + 16

x² = 289 - 16 = 273

x = √273

x = 16.5 units

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Any vertical line has undefined slope.
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Help me I need the answer on paper help me now
Viktor [21]

Answer:

a) k = 10              b) k = 7.5

Step-by-step explanation:

<h3><u><em>a)</em></u></h3>

( 5k+ 20 ) + ( 7k + 40 ) = 180

12k + 60 = 180

12k = 120

k = 10

<h3><u><em>b)</em></u></h3>

40 + ( 12k + 10) + 180 - ( 8k + 80 ) = 180

50 + 12k + 180 - 8k - 80 = 180

50 + 12k -8k - 80 = 0

50 + 4k - 80 = 0

30 = 4k

k = 7.5

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2 years ago
Help w one question plz
GarryVolchara [31]

Answer:

B is the right answer

Step-by-step explanation:

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3 years ago
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Which is the graph of y= 2(x-3)^2 +2
WINSTONCH [101]

The graph of y = 2(x - 3)² + 2 can be seen in the attached picture. This problem can be solved through the concept of parabola and transformation.

<h3>Further explanation</h3>

<u>The Problem:</u>

Which is the graph of y = 2(x - 3)² + 2?

<u>Question-1:</u>

How to make a graph y = 2 (x - 3) ² + 2 through the concept of a parabola.

<u>The Process:</u>

The equation of a parabola is given by \boxed{ \ y = a(x - h)^2 + k \ }.

Keep in mind the following points:

  • vertex point at (h, k)
  • axis of symmetry at x = h
  • a > 0 the parabola opens upward
  • a < 0 the parabola opens downward
  • the y-intercept is \boxed{ \ y = ah^2 + k \ } at x = 0.

From our case it can be concluded as follows:

  • the graph of y = 2(x - 3)² + 2 opens upward
  • vertex point at (3, 2)
  • axis of symmetry at x = 3
  • the y-intercept is 2(3²) + 2 = 20 or in coordinates of (0, 20)

<u>Question-2:</u>

How to make the graph of y = 2(x - 3)² + 2 through the transformation.

<u>The Process:</u>

To plot the graph of y = 2(x - 3) ² + 2 we apply for the following transformation order:

Step-1: clearly, to obtain the graph of y = (x - 3)² we shift the graph of y = x² to the right 3 units.

Step-2: to obtain the graph of y = 2(x - 3)², we stretch the graph of y = (x - 3)²  by a factor of 2 (in other words, multiply each y-coordinate by 2).

Step-3: finally, to obtain the graph of y = 2(x - 3)² + 2 we shift the graph of y = 2(x - 3)² upward 3 units.

Thus the construction of the graph y = 2 (x - 3) ² + 2 is completed.

The graph of y = 2(x - 3) ² + 2 is drawn by the combination of shifting the graph of y = x² to the right 3 units and upward 2 units, and also stretch by a factor of 2. Between vertical shift and stretch steps, it is the same whatever steps are taken first.

- - - - - - - - - -

Notes

  • The transformation of graphs is changing the shape and location of a graph.  
  • There are four types of transformation geometry: translation (or shifting), reflection, rotation, and dilation (or stretching/shrinking).  
  • In this case, the transformation is shifting horizontally and vertically and also stretching vertically.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.  
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Hence, the combination of vertical and horizontal shifts is as follows:  

\boxed{ \ y = f(x \pm h) \pm v \ }  

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right .

Notice the following definitions for stretch and shrink.

  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = cf(x)} by stretching \boxed{ \ c > 1 \ } or shrinking \boxed{ \ 0 < c < 1 \ } the graph of \boxed{y = f(x)} vertically by a factor of c.
  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = f(cx)} by stretching \boxed{ \ 0 < c < 1 \ } or shrinking \boxed{ \ c > 1 \ } the graph of \boxed{y = f(x)} horizontally by a factor of c.
<h3>Learn more  </h3>
  1. What is the y-intercept of the quadratic function  f(x) = (x – 6)(x – 2)? brainly.com/question/1332667
  2. Transformations that change the graph of (f)x to the graph of g(x) brainly.com/question/2415963
  3. Which statement correctly describes the graph  brainly.com/question/10929552

8 0
3 years ago
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Enter the inequality given by the graph below.
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