Answer:
attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Step-by-step explanation:
Each bit has two options. So
How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?
So for each of the 64 bits, we have the following number of options.
2 - 2 - 2 - 2 -... - 2
So, in all, there are
options.
So, attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
128 bits long?
Using the same logic as the first question.
So, attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Answer:
B: (x + 2)(x - 3)^2
Step-by-step explanation:
This is only going to have 3 roots. One of them is (x - 3)
D does not look right. So let's solve it using synthetic division.
3 || 1 - 4 -3 18
3 -3 -18
========================
1 -1 -6 0
So what you have is a quadratic
- x^2 - x - 6 = 0 which will factor
- (x - 3)(x + 2) = 0
- x - 3 = 0
- x = 3
- x + 2 =0
- x = - 2
- (x - 3)(x - 3)(x + 2 ) = 0
The answer is B
Answer:
x=10
Step-by-step explanation:
x+ 5= 3x - 21 +6
x+5 = 3x - 15
20= 2x
Answer:
-52.5 or -53
Step-by-step explanation:
Start by subtracting 18 from both sides. With you get 0.4=-21. Now divide 0.4 into both sides.
