SUSPECT #077802

The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 11 nursing s

Fofino [41]

Answer:

There is enough evidence to claim that population mean 1 is less than population 2 at the 0.05 significance level.

Step-by-step explanation:

We are given the following in the question:

Group 1:

$\mu_1 = 63.3\\\sigma_1 = 3.7\\n_1 = 11$

Group 2:

$\mu_2 = 70.2\\\sigma_2 = 6.6\\n_2 = 13$

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu_1 \geq \mu_2\\H_A: \mu_1 < \mu_2$

Since, the population variances are equal and that the two populations are normally distributed, we use t-test(pooled test) for difference of two means.

Formula:

Pooled standard deviation

$s_p = \sqrt{\displaystyle\frac{(n_1-1)\sigma_1^2 + (n_2-1)\sigma_2^2 }{n_1 + n_2 - 2}}$

$t_{stat} = \displaystyle\frac{\mu_1-\mu_2}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

$\text{Degree of freedom} = n_1 + n_2 - 2$

Putting all the values we get:

$s_p = \sqrt{\displaystyle\frac{(11-1)(3.7)^2 + (13-1)(6.6)^2 }{11 + 13 - 2}} = \sqrt{29.9827} = 5.48$

$t_{stat} = \displaystyle\frac{63.3-70.2}{5.48\sqrt{\frac{1}{11}+\frac{1}{13}}} = -3.073$

$\text{Degree of freedom} = 11 + 13 - 2 = 22$

Now,

$t_{critical} \text{ at 0.05 level of significance, 22 degree of freedom } = -1.717$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject the null hypothesis. We accept the alternate hypothesis.

We conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2.

There is enough evidence to claim that population mean 1 is less than population 2 at the 0.05 significance level.

6 0

3 years ago

The midpoint, M , of segment AB has coordinates (2,−1) . If endpoint A of the segment has coordinates (−3,5) , what are the coor

lbvjy [14]

the coordinates of endpoint B are (7,7)

Answer:

Solution given:

M(x,y)=(2,-1)

A $(x_{1},y_{1})=(-3,5)$

Let

B $(x_{2},y_{2})=(a,b)$

now

by using mid point formula

x= $\frac{x_{1}+x_{2}}{2}$

$ubstituting value

2*2=-3+a

a=4+3

a=7

again

y= $\frac{y_{1}+y_{2}}{2}$

$ubstituting value

-1*2=5-b

b=5+2

b=7

the coordinates of endpoint B are (7,7)

8 0

3 years ago

SHOW UR WORK PLEASE IM LTERALLY CRYING

GalinKa [24]

Answer : 6 pieces
first you need to convert 3/4ths into 8th so you multiply
3/4 * 2 = 6/8
you can get 6 pieces of ribbon

4 0

3 years ago

1.825 rounded to the nearest hundredth

Alenkinab [10]

The answer is 1.83
you look to the number after the hundreds place which is 5. the rule is that is that place is 5 or more then you can round up with the hundreds place which turned the 2 into a 3

4 0

3 years ago

Please help Divide. 9u2− 12u/3u

podryga [215]

It has to be at lest 9u2-4?

3 0

3 years ago