For this case we have the following equation:
To solve we follow the steps below:
We add similar terms from the left side of the equation:
We divide between 6 on both sides of the equation:
Finally, we have to:
Answer:
Okay. In my opinion, all the class has to do is simplify the expressions and compare. But they want to substitute instead.
Well then.
First, let's notice that these are linear expressions, meaning that if they are equivalent then all their values match up.
Number 1 is not a good one. Just because they're both positive doesn't mean anything; they have to be <em>the same.</em>
This also eliminates 3.
Number 2 is a good one, but it's not as reliable. If, for instance, the two expressions are <em>not </em>equivalent and you get lucky enough to pick that one value they intersect at (or have in common), then you'd be wrong when you say they are equivalent.
Number 4 makes the most sense because if both expressions are equivalent, then every value matches up. If not, then only one will. So having two values to substitute will most definitely answer the class question.
Hope this helps, let me know if I messed up! ;)
Because anything multiplied by one is that number. If you have 3/4 one time, then it is 3/4.
Answer:
The area of A is nine times the area of B.
Step-by-step explanation:
Answer:
cos(52°) = 18/x
x = 18·sec(52°)
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
Cos = Adjacent/Hypotenuse
In this geometry, that means ...
cos(52°) = 18/x
You can use the relation sec(x) = 1/cos(x) to rewrite this as ...
x = 18·sec(52°)
_____
You can also use the complementary angle and the complementary trig function.
sin(90° -52°) = 18/x
