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asambeis [7]
3 years ago
8

P = 0.5e - 5 to determine P

Mathematics
1 answer:
ipn [44]3 years ago
6 0

Answer:

Let's solve your equation step-by-step.

p=(0.5)(2.718282)−5

Step 1: Simplify both sides of the equation.

p=(0.5)(2.718282)−5

p=1.359141+−5

p=(1.359141+−5)(Combine Like Terms)

p=−3.640859

p=−3.640859

Answer:

p=−3.640859

Step-by-step explanation:

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Answer:

  (a) scalene, see attachment

  (b) acute, see attachment

  (c) correct; isosceles

Step-by-step explanation:

(a) The sides of the triangle all have different lengths, so the triangle is scalene. Differences in coordinates between the points of the triangle are (6, 2), (5, 2), and (4, 1), so no two distances between these points can be the same.

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(b) The angle opposite the longest side is clearly an acute angle, so the triangle is an acute triangle.

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(c) Miles and Brad live on the same north/south line. Jose lives at a distance that is halfway between those houses in the north-south direction. Hence the distance to Miles' and Brad's houses must be the same from Jose's house. That means the triangle connecting Miles', Brad's, and Jose's houses will be an isosceles triangle.

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4 years ago
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MakcuM [25]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Find the slope of the line that passes through<br> (10, 1) and (6,2)
Daniel [21]

Answer:

m=-1/4

Step-by-step explanation:

2-1/6-10=1/-4

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7 0
3 years ago
Read 2 more answers
4. What is the circumference of a circle whose area is 81π cm squared?
vichka [17]
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Step 1: find the radius from area
81pi=pi*r^2
81=r^2
9=r

Step 2: plug in radius to the circumference equation

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7 0
3 years ago
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For some reason my teacher gave this to us and I kinda forgot how to do this from last year... please helppp w/ work or she’s go
WARRIOR [948]
The greatest common factor is...
5a
I got this by...
10: 1,2,5,10
15: 1,3,5,15
25: 1,5,25
The GCF is 5 for the numbers.
For the a's, it's...
a: a
a^3: a×a×a
a^6: a×a×a×a×a×a
The GFC is a.
Then multiple 5 and a, and you get...
5a
The GFC is...
5a
Hope this helps!
8 0
3 years ago
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