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erastova [34]
4 years ago
6

The perimeter of a rectangle is 38 ft. The length is 9 ft longer than the width. Find the demensions. Write a system of linear e

quations and solve the resulting system. Let x be length and y be width.
Mathematics
1 answer:
nikdorinn [45]4 years ago
8 0
P=38
P=2x+2y=2(x+y)
x=9+y



so
38=P=2(x+y)
38=2(x+y)
divide both sides by 2
19=x+y
x=9+y
19=9+y+y
19=9+2y
minus 9 both sides
10=2y
divide by 2
5=y
sub back
x=9+y
x=9+5
x=14


x=14
y=5
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Please help!!!!!!! it would be very appreciated
Pani-rosa [81]

Answer:

x = 17.5 and y = 35

Step-by-step explanation:

2x + 10 = y + 10 ( alternate angles )

subtract 10 from both sides

2x = y ⇒ 6x = 3y → (1)

the sum of the 3 angles in the triangle = 180°

6x + y + 10 + 30 = 180 ( replace 6x by 3y )

3y + y + 40 = 180

4y + 40 = 180 ( subtract 40 from both sides )

4y = 140 ( divide both sides by 4 )

y = 35

substitute y = 35 into (1)

2x = 35 ( divide both sides by 2 )

x = 17.5



5 0
3 years ago
Jordan already knew 2 appetizer recipes before starting culinary school, and he will learn 2 new appetizer recipes during each w
kirill115 [55]

Answer:

w=2r

r= w/2

r- w/2 = 0

w -2r= 0

Step-by-step explanation:

Let w be the number of weeks and r be the number of recipes learnt . So he will learn 2 recipes each week .Equating gives

w=2r

when w= 1

w= 2(1) = 2

For 1st week 2 recipes are learned

when w= 2

w= 2( 2) = 4

For 2nd week 4 recipes are learned.

or

when r= 2

r= w/2

r =2/2  = 1  one  recipe is learned in half of the week  

r- w/2 = 0

or

w -2r= 0

6 0
3 years ago
Find the sum or difference 7/8 + 9/16
zavuch27 [327]

Answer:

The answer is 23/16 but if you want it to be a mixed number, it is 1 7/16.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Help please!!!!!!!!!!!!!!!!
meriva

Answer:

3

Step-by-step explanation:

they always make some kind of angle usually 90 degress.

7 0
3 years ago
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nekit [7.7K]

\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1


when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.


quick note:

when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.

6 0
3 years ago
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