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choli [55]
3 years ago
15

Please help me!!!! Thank you so much! I’m giving away 25 points for this one! I need both the problems solved

Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0
23. a. Mn undergoes oxidation
b. S undergoes oxidation

24. a. Oxidizing agent - CuO
Reducing agent - H2
b. Oxidizing agent - PbO
Reducing agent - CO
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Plz help! NO FAKE ANSWERS PLEASE
aleksklad [387]

Answer:

postion emmsion

Alpha decaya

gamma decay

beta decay

in order

Explanation:

and there is 100% of humans dieing becasue of atoms decays which is sad and also answers the question does life have meeain and no we are all going to die anyways

7 0
2 years ago
Read 2 more answers
I need help!! Following measurements
Anna71 [15]
I am so sorry I do not know but I need to answer a question in order to ask one I hope u pass:))
5 0
2 years ago
The most reactive metals are the ________ to corrode.
katrin [286]

Answer:

2. quickest

Explanation:

because they have lower activation energy.

3 0
2 years ago
Banda se los agradeceria de corazon si me ayudarian con esta tarea :c
morpeh [17]

Answer:

ver explicacion

Explanation:

Zn (s) + 2HCl (ac) ---> ZnCl2 (ac) + H2 (g)

El zinc se oxida y el hidrógeno se reduce. HCl es el agente oxidante mientras que Zn es el agente reductor.

2Na (s) + H2SO4 (ac) ----> Na2SO4 (ac) + H2 (g)

El Na se oxida y el hidrógeno se reduce. El ácido sulfúrico es el agente oxidante, mientras que el sodio metálico es el agente reductor de tge.

Ca (OH) 2 (ac) + H2CO3 (ac) ------> CaCO3 (s) + 2H2O (l)

Esta no es una reacción redox ya que no hay cambios en el número de oxidación de izquierda a derecha.

4 0
2 years ago
i have an unknown volume of gas at a pressure of 0.50 atm a temperature of 325 k. If i raise the pressure to 1.2 atm, decrease t
Ronch [10]
Assuming that the number of mols are constant for both conditions:
\frac{P_1V_1}{T_1} =  \frac{P_2V_2}{T_2}
Now you plug in the given values. V_1 is the unknown. 
\frac{0.50 atm*V_1}{325K} = \frac{1.2 atm* 48 L}{230K}

Separate V_1
V_1= \frac{1.2 atm* 48 L * 325K }{230K*0.50 atm }
V= 162.782608696 L 

There are 2 sig figs

V= 160 L
3 0
2 years ago
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