The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
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8.1moles
Explanation:
Given parameters:
Mass of water to be decomposed = 29.2g
Unknown:
Number of moles of oxygen.
Solution:
To solve this problem, we first write the balanced reaction equation :
2H₂O → 2H₂ + O₂
Now convert the given mass of the water to number of moles;
Number of moles of water = 
Molar mass of water = 2(1) + 16 = 18g/mol
Number of moles of water = 
= 16.2moles
From the balanced reaction equation:
2 moles of water produced 1 mole of oxygen gas;
16.2 mole of water will produce 
= 8.1moles of oxygen gas
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A volcano is created when hot molten rock, ash and gases escape from an opening in the Earth's surface. The molten rock and ash solidify as they cool, forming the distinctive volcano shape shown here. As a volcano erupts, it spills lava that flows downslope. Hot ash and gases are thrown into the air.
Answer:
N2O5
Explanation:
IUPAC ID: Dinitrogen pentoxide
Molar mass: 108.01 g/mol
Density: 1.64 g/cm³
