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wariber [46]
3 years ago
8

Jackson has three cartons of gumball ther are 100 boxes in each cartoon

Mathematics
2 answers:
alexira [117]3 years ago
4 0

Answer:yes

Step-by-step explanation:yes

Vaselesa [24]3 years ago
4 0

Answer:

300 boxes

Step-by-step explanation:

You didn't really add the whole question but if you want to find how many boxes are there in all you have to multiply 100 by 3 to get 300.

Hopefully that helps and have a great day!

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Three consecutive even integers have a sum 78
andreev551 [17]
The answer is 24, 26, and 28
6 0
3 years ago
A circle has a radius of 12.6 cm.
d1i1m1o1n [39]
Circumference = 2 * PI * radius
circumference = 2 * PI * 12.6
If the central angle is 120°, then the arc will be exactly one third of the circumference.
arc length = (2 * PI * 12.6) / 3
arc length = 8.4 PI


5 0
3 years ago
MULTIPLE CHOICE HELP ASAP! Brainliest for correct answer.
N76 [4]

Answer:

An equation of the circle with centre (-2,1) and radius 3 is \mathbf{(x+2)^2+(x-1)^2=9}

Option D is correct.

Step-by-step explanation:

Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3

The equation of circle is of form: (x-h)^2+(x-k)^2=r^2 where (h,k) is centre and r is radius.

We have centre C (-2,1) so, we have h = -2 and k = 1

We have radius = 3 so, r = 3

Putting values in the equation and finding the required equation:

(x-h)^2+(x-k)^2=r^2\\(x-(-2))^2+(x-1)^2=(3)^2\\(x+2)^2+(x-1)^2=9

So,  an equation of the circle with centre (-2,1) and radius 3 is \mathbf{(x+2)^2+(x-1)^2=9}

Option D is correct.

7 0
2 years ago
Plss help me with this do not add any links or they will be reported and plss do not answer just for the points thank you!!!!!!
Sonbull [250]

Answer:

x=-4/3+y/3. y=-11/4+3x/4

Tap to view steps...

4 0
2 years ago
Read 2 more answers
Is it possible for a simple, connected graph that has n vertices all of different degrees? Explain why or why not.
ryzh [129]

Answer:

It isn't possible.

Step-by-step explanation:

Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.

Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.

Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.

8 0
3 years ago
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