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Bas_tet [7]
3 years ago
14

The top of a ladder rests at a height of 15 feet against the side of a house. If the base of the ladder is 6 feet from the house

, what is the length of the ladder? Round to the nearest foot.
Mathematics
1 answer:
Advocard [28]3 years ago
4 0

Answer:

The length of the ladder is 16\ ft

Step-by-step explanation:

Let

L ----> the length of the ladder

we know that

Applying the Pythagoras theorem

L^{2}=15^{2} +6^{2}

L^{2}=261

L=\sqrt{261}\ ft

L=16\ ft

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Need help with finding the surface area and volume for this please thanks I just need step by step help so I can understand it m
Allisa [31]

Answer:

144

Step-by-step explanation:

First, do the top and bottom. The top is 2*4*3 or 24, and the bottom is 6*4 or 24.

Now, do the sides. It is a staircase that you can split into 6 2x2 blocks, or 6*4=24. Do the same with the other side to get 24 again.

Now for the front and back. This is 2*4*3 and 6*4 again, or 24 and 24.

Now you have 6 24's so just multiply these and get 144.

6 0
3 years ago
What is the answer to this equation -20 +(-9)
ANTONII [103]

Answer:

-29

Step-by-step explanation:

they are both negative so u add them.

3 0
3 years ago
Read 2 more answers
What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
3 years ago
Simplify - root (9+y)^2 if y <-10
nevsk [136]

Answer:

− √ ( 9 + y ) 2 > 1

Explanation:

− √ ( 9 + y ) 2 , where  y < − 10

Simplify the expression,

− √ ( 9 + y ) 2 = − ( 9 + y ) = − 9 − y

When  y < − 10 , − y > 10

Subtract  9  from both sides,

− 9 − y > 1  Hence,

− √ ( 9 + y ) 2 > 1

6 0
3 years ago
If you don't have two rays, can you have an angle?
Triss [41]

Answer:

  Yes

Step-by-step explanation:

You can define an angle of interest at any point of intersection of any real or virtual lines, curves, planes, or surfaces, or combination thereof. We often measure the angle between our present location and two different other locations (horizon, stars, objects of one sort or another). The "rays" involved are virtual (non-existent, imaginary, conceptual) rather than real. We also often measure angles between real physical objects, things other than the idealized set of infinitesimal points that make up a ray.

6 0
3 years ago
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