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coldgirl [10]
3 years ago
10

What is the domain and range of the relation shown?

Mathematics
2 answers:
Helga [31]3 years ago
5 0

Answer:

A.

{-4 ≤ x ≤ 4}

{-4 ≤ y ≤ 4}

Step-by-step explanation:

We’ll domain is the amount of x values,

Range is the amount of y values

_______________________________

Domain:

Starts from -4 to 4

{-4 ≤ x ≤ 4}

I made the sign less than or equal to because the circle lines are solid.

Range:

This starts from -4 to 4 also.

{-4 ≤ y ≤ 4}

<em>Thus,</em>

<em>answer choices A. is correct</em>

<em />

<em>Hope this helps :)</em>

raketka [301]3 years ago
5 0

Hey there! I'm happy to help!

Note that this is not a function because some inputs can have more than one output, that's why they say relation, not function! :D

DOMAIN

The domain is all of the possible x-values of the relation.  We see that the lowest x-value is -4, while the highest is 4. If you plug in these two or any number in between, there will be at least one corresponding output.

This domain can be written as -4 ≤ x ≤ 4.

RANGE

The range is all of the possible outputs or y-values. We see that the minimum y-value is -4 and that the highest is 4. Therefore, we will just write it the same as the domain but use a different variable.

-4 ≤ y ≤ 4.

This matches with Option A.

I hope that this helps! Have a wonderful day!

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Step by step explanation:

To solve the expression 15=\frac{x}{6}-1, and obtaining a value for x we can do the following:

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  2. Multiply both sides by 6, which yields 15\times6=\frac{x}{6}\times6. This results in 90=x.

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andreyandreev [35.5K]

The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

Step-by-step explanation:

The given is,

                  The sum of two numbers is 21

                   The second number is six times the first number

Step:1

          Let, m - First number

                  n - Second number

Step:2

        From given,

                  n - 6m     ( The second number is six times the first number )

        Equation becomes,

                  Sum = m + n

        Where,

                      21 = m + ( 6m )

                       21 = 7m

                       m = 3

        Substitute m value n becomes,

                        n = 6m

                           = (6 × 3)

                      n  = 18

Result:

          The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

                   

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