You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36
36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3
To find the slope, divide a/b and you will get 2/3.
Multiply everything in the parenthesis by 3.
9x - 24 = 4x + 6
Add 24 to both sides.
9x = 4x + 30
Subtract 4x from both sides.
5x = 30
Divide both sides by 5.
x = 6
Hope this helps!
I don’t have the time to do this, but there is a app called Socratic where you can take a pic of your homework and it searches everything on google.
That’s how I got Brainly
Answer:
0.75 oz
Step-by-step explanation:
8 cats divided by 6-oz cans=0.75 oz each
Answer:
the container is 1/4 full at 9:58 AM
Step-by-step explanation:
since the volume doubles every minute , the formula for calculating the volume V at any time t is
V(t)=V₀*2^-t , where t is in minutes back from 10 AM and V₀= container volume
thus for t=1 min (9:59 AM) the volume is V₁=V₀/2 (half of the initial one) , for t=2 (9:58 AM) is V₂=V₁/2=V₀/4 ...
therefore when the container is 1/4 full the volume is V=V₀/4 , thus replacing in the equation we obtain
V=V₀*2^-t
V₀/4 = V₀*2^-t
1/4 = 2^-t
appling logarithms
ln (1/4) = -t* ln 2
t = - ln (1/4)/ln 2 = ln 4 /ln 2 = 2*ln 2 / ln 2 = 2
thus t=2 min before 10 AM → 9:58 AM
therefore the container is 1/4 full at 9:58 AM
