We have to break each degree in terms of 90
A) 
Which is in third quadrant, therefore sine is negative hence

B) 
Which is in third quadrant, therefore cosine is negative hence

C) 
Which is in third quadrant, therefore tangent is positive hence

D) 
Which is in third quadrant, therefore cosec is negative hence
not defined
E)
Which is in third quadrant, therefore secant is negative hence

F) 
Which is in third quadrant, therefore tangent is positive hence
not defined
Hence only
and
have value -1
Hope this will help
I believe the answer is 2
Answer:
x = -35
Step-by-step explanation:
x + 2y + 3 = 0
Subtract x from both sides.
2y + 3 = -x
Subtract 3 from both sides.
2y = -x - 3
Divide by 2 on both sides
y = -(x+3)/2
x + y + 4 = 0
Subtract x and 4 from both sides
y = -x - 4
3x - 2y + 4 = 0
Subtract 3x and 4 from both sides.
-2y = -3x -4
Divide by -2 from both sides.
y = -(3x + 4) / 2
The answer is the graph that contains these slopes and lines on the graph, which was not provided.