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3 years ago

What is the least common multiple of 8 and 11

Mathematics

1 answer:

tino4ka555 [31]3 years ago

7 0

Answer:

Step-by-step explanation:

Find the prime factorization of both 8 and 11.

8 → 4 × 2 → 2 × 2 × 2

11 → 11

Then, multiply each factor the greater number of times it occurs. Since no factors are duplicated between 8 and 11 (as in, 2 is not a factor of 11, nor is 11 a factor of 8), LCM will equal 2 × 2 × 2 × 11.

2 × 2 × 2 × 11 = 88, so the LCM is 88.

It's a little hard to explain without visuals. A video could be useful, though I can't put links here.

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Make up a story that can be represented by y=4x

Papessa [141]

Jeff is selling Raspberry Pi cases for $4 dollars. If Jeff sells 5 Raspberry Pi cases, how much will he make off the sale?

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3 years ago

The length of a rectangle is 8cm and the height is 16cm find the answer of the above figures using this formular...

notsponge [240]

Length=8cm
Breadth=16cm(Height)

<h3>Perimeter:-</h3>

$\\ \sf\longmapsto Perimeter=2(L+B)$

$\\ \sf\longmapsto Perimeter=2(16+8)$

$\\ \sf\longmapsto Perimeter=2(24)$

$\\ \sf\longmapsto Perimeter=48cm$

Area:-

$\\ \sf\longmapsto Area=Length\times Breadth$

$\\ \sf\longmapsto Area=8(16)$

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3 years ago

Which expression is equivalent to 2+3

disa [49]

Answer:

Step-by-step explanation:

1. 9x^5

2. 9x^6

3. 27x^5

4. 27x^6

3 0

3 years ago

Read 2 more answers

What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

Ratling [72]

we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

$(30 a^{2+k})(b^{3+1})$

$30a^{2+k}b^{4}$

now, we can equate it with right side

and we get

$30a^{2+k}b^{4}=30a^6 b^4$

We can see that both sides have 30 , a and b

and they are equal

so, exponent of a must also be equal

$2+k=6$

now, we can solve for k

$2+k-2=6-2$

$k=4$ ................Answer

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4 years ago

Read 2 more answers

Find f(g(-4)) and g(f(-4)) using the functions below.<br><br> f(x) = 2x + 7<br> g(x) = x2 + 3x - 1

daser333 [38]

Answer:

f(g(-4)) = 13.

g(f(-4)) = -3.

Step-by-step explanation:

g(-4) = (-4)^2 + 3(-4) - 1

= 3.

so f(g(-4))

= f(3)

= 2(3) + 7

= 13.

f(-4) = 2(-4) + 7

= -1.

so g (f(-4))

= g(-1)

= (-1)^2 - 3 - 1

= -3.

8 0

4 years ago