All categories

3 years ago

Identify a pair of vertical angles in the figure

Mathematics

1 answer:

Virty [35]3 years ago

6 0

There are a lot of vertical angles in this figure, I will try my best to list most of them; ace,bcg bca, ecg gfd,afe gfe, dfa

You might be interested in

Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an

ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b) P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0

3 years ago

A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult

klio [65]

Answer:

Probability that the spinner will stop on an odd number or a multiple of 5 is 0.6

Step-by-step explanation:

Probability = $\frac{Required outcomes}{Total possible outcomes}$

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

Total possible outcomes: 20

Outcomes that spinner will stop on an odd number, n(Odd): 10

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = $\frac{n(Odd)}{Total}$ = $\frac{10}{20}$ = $\frac{1}{2}$ = 0.5

Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = $\frac{n(5)}{Total}$ = $\frac{4}{20}$ = $\frac{1}{5}$ = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = $\frac{2}{20}=\frac{1}{10}=0.1$

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0

3 years ago

Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of e

emmainna [20.7K]

This question is incomplete, the complete question is;

Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of equations in terms of x, y, z, and t.) The line passes through the point (3, 1, 2) and is parallel to the line given by x = y = z.

Answer:

the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

Step-by-step explanation:

Given that;

line x = y = z and point ( 3, 1, 2 )

the given line can be written as;

[x-0 / 1] = [y-0 / 1] = [z-0 / 1]

if two lines are parallel directional ratios are equal.

so DIRECTIONAL RATIOS of given line is ( 1, 1, 1 )

therefore required line is;

[x-3 / 1] = [y-1 / 1] = [z-2 / 1] = t

⇒ [x-3 / 1] = t

x = t+3

[y-1 / 1] = t

y = t+1

[z-2 / 1] = t

z = t+2

Therefore the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

8 0

3 years ago

Helppp pt.5 plzzzzz

Fiesta28 [93]

Answer: 60 cm²

Step-by-step explanation:

This is pretty simple, we know AB is 12 cm and DE is 4 cm. We know ABC has a total of 180 square centimeters. So...

12 ÷ 3 = 4

180 ÷ 3 = 60

The answer is 60 cm²

I hope this helps!

6 0

3 years ago

I need help on number 2

Nina [5.8K]

9514 1404 393

Answer:

a. 405

b. -2

c. 5

d. 43

Step-by-step explanation:

I don't like doing arithmetic any more than you do, so I let a calculator do it for me. A spreadsheet works well for this, too. The function values are shown in the attachment.

Put the function argument where the variable is and do the arithmetic.

a. h(4) = 5·3^4 = 405

b. d(2) = 7 -9(2 -1) = -2

c. h(0) = 5·3^0 = 5

d. d(-3) = 7 -9(-3 -1) = 43

7 0

3 years ago