Answer:
oooooooffff
Step-by-step explanation:
Answer:
Step-by-step explanation:
Since you didn't state what you're looking for, I will lost out all the angles in the picture instead.
Given that
∠CEF = 150°
∠ECA = 32°
∠CEA = 180 - ∠CEF(angles in a straight line)
∠CEA = 180 - 150
∠CEA = 30°
∠EAC = 180 - ∠CEA - ∠ECA(angles in a triangle)
∠EAC = 180 - 30 - 32
∠EAC = 118°
∠CAB = 180 - ∠EAC(angles in a triangle)
∠CAB = 180 - 118
∠CAB = 62°
∠ACB = ∠CEA = 30°(similar angles)
∠ABC = 180 - ∠CAB - ∠ACB(angles in a triangle)
∠ABC = 180 - 62 - 30
∠ABC = 88°
∠ECB = ∠ECA + ∠ACB(angles in a triangle)
∠ECB = 32 + 30
∠ECB = 62°
∠CEA + ∠ECB + ∠ABC = 180
30 + 62 + 88 = 180°.
Please give brainliest if it helped you <3
For the function to be differentiable, its derivative has to exist everywhere, which means the derivative itself must be continuous. Differentiating gives

The question mark is a placeholder, and if the derivative is to be continuous, then the question mark will have the same value as the limit as

from either side.


So the derivative will be continuous as long as

For the function to be differentiable everywhere, we need to require that

is itself continuous, which means the following limits should be the same:



So, the function should be

with derivative
Answer:
hmmmm
Step-by-step explanation: