= 3when x-What is the value for f(x) = 3^2x+1 when x=1/236915
1 answer:
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Answer: Option a.
Step-by-step explanation:
Make the denominator equal to zero and solve for x:
Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:
Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2
The answer is the option a.
On the unit cirlce, the cosine of an angle is negative whenever the angle falls in the interval
If you recall your special triangles, this cosine occurs for angles of
More generally, this occurs for
Answer:
Step-by-step explanation:
Hope it helps you
