= 3when x-What is the value for f(x) = 3^2x+1 when x=1/236915
1 answer:
You might be interested in
Answer:
Option b. Two solutions
Step-by-step explanation:
In order to find how many real number solutions the equation has we have to solve it
Given equation: -4x² + 10x + 6 = 0
taking 2 common from the equation
2(-2x² + 5x + 3) = 0
-2x² + 5x + 3 = 0
taking minus sign common from the above equation
2x² - 5x - 3 = 0
We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²
2x² - 6x + x - 3 = 0
taking common above
2x(x-3) + 1(x-3) = 0
taking (x-3) common
(2x+1)(x-3) = 0
2x + 1 = 0
2x = -1
x =
x - 3 = 0; x = 3
the solutions are
Both values are real numbers, therefore correct option is b
Answer:
The decimal point should be moved Six places to the right side because there are Six zeros in 10 to the power of 6.
Step-by-step explanation:
As we have to represent the number in the form of we need to move the decimal Six places towards left because there are Six zeros in
i.e. 1000000. For this purpose we will add four zeros to the left of the number.
So the number in the format mentioned in question will look like -
0.00003405 × .