3(x + 1) = -2(x - 1) - 4.
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Given:
'a' and 'b' are the intercepts made by a straight-line with the co- ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get
Multiply both sides by a.
The value of a is 2. So, x-intercept is 2.
Putting a=2 in , we get
The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get
Therefore, the equation of the required line in intercept form is .