The graph of the piecewise function includes
(1) a straight line passing through point (-3, 0) and stopping at point (0, 3) with an unshaded small circle at the end of point (0, 3) and an arrow at the other end.
(2) a shaded small circle at point (0, 5), and
(3) a straight line starting at the point (0, -1) and passing through the point (2, 3) with an unshaded small circle at the point (0, -1) and an arrow at the other end.
So, x = 13, x = √3 and x =7i.
now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.
now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.
Answer:
132 degrees
Step-by-step explanation:
To solve this problem, you need to know a couple of rules
1) Inscribed angle theroem: when an angle is inscribed in a circle and touches the other end (as opposed to ending at the diameter of the circle), the measure of this angle is half of the measure of the arc.
2)Angles of a quadrilateral shape add up to 360 degrees.
3) The angles inside a circle and the angles of the circles arclength adds up to 360 degrees.
So first, solve angle S with inscribed angle theorem. 126/2 = 63
Then, use the rule that all arc angles in a circle add up to 360 degrees to find the arc angle from Q to S. 360-90-126 = 144. Now find angle P with inscribed angle theorem by doing 144/2 = 72.
Now, use the rule that all angles in a quadrilateral add up to 360 to find R. 360-93-72-63 = 132.
Let me know if this doesn't work, I'll look at it again.
