All categories

3 years ago

Express 231 as a product of prime factors

1 answer:

6 0

The product of prime factors basically means to find the prime factors of this number and put them into an equation.

The answer to this question is 3 * 7 * 11

You might be interested in

How do u figure out the X and Y of Y=2x+1

MAXImum [283]

Answer:

https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-linear-equations-functions/8th-x-and-y-intercepts/v/x-and-y-intercepts-2

Step-by-step explanation:

This is a video that would hopefully explain it better than I could

3 0

3 years ago

Read 2 more answers

For the simple linear equation below, what is the y-coordinate of the ordered pair when the x-coordinate is −5?

NARA [144]

Answer:

-9

Step-by-step explanation:

7 0

3 years ago

What is the greatest common factors of 60w,34w^2,and 24w^4

andrew11 [14]

Answer: 2w

Step-by-step explanation:

The greatest common factor could also be referred to as the Highest common factor. Now

60w, 34w² and 24w⁴

Now let concert each to its factors

60 = 2 × 2 × 3 × 5 × w

34w² = 2 × 17 × w × w

24w⁴ = 2 × 2 × 2 × 3 × w × w × w × w

Therefore H.C.F or the greatest common factor

G.C.F = 2 × w

= 2w

4 0

3 years ago

Solve the system of equations. −4x+3y=−2 y=x−1 x- y-

Kobotan [32]

Answer: x= -1

y= -2

Step-by-step explanation:

-4x+3y= -2

y=x-1

-------------------

-4x+3(x-1)= -2

-4x+3x-3= -2

-x=1

x= -1

y=-1-1

y=-2

6 0

4 years ago

Read 2 more answers

Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m

JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment .

A) Determine the test statistic

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5) / $\sqrt{0.5*0.5 / 200}$ = 2.12

b) determine the p-value

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 ) = 1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0

3 years ago