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uranmaximum [27]
3 years ago
14

Find a formula for the nth term

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

a_{n} = - 1.3n - 2.4

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference, thus

a_{n} = - 3.7 - 1.3(n - 1) = - 3.7 - 1.3n + 1.3 = - 1.3n - 2.4

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The average is 5.41666667 degrees.

Step-by-step explanation:

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3 years ago
2. Find the fraction which is exactly halfway between 1/7 and 4/7​
Ksivusya [100]

Answer:

That would be the fraction exactly between 2/7 and 3/7

which would be 2.5 / 7 or 5 / 14

Step-by-step explanation:

4 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
Explain how you can use absolute value to tell whether
kicyunya [14]

Answer:

Let the integers are p and q.

In case both integers are positive or negative, you add the numbers up and apply their sign to the sum.

<u>Examples:</u>

  • 10 + 88 = 98
  • -20 + (-15) = -35

In case one of the integers is negative and one positive.

  • p < 0, q > 0

Use absolute value in this case.

Subtract the numbers and apply the sign of the number with the greater absolute value.

<u>Examples:</u>

  • - 10 + 15 = |15 - 10| = |5| = 5
  • - 15 + 10 = - |15 - 10| = - |5| = -5
3 0
3 years ago
Find the least common multiple of x2 – 8x + 12 and x2 – x – 2.
abruzzese [7]
<span>The least common multiple of x² – 8x + 12 and x² – x – 2.

by factoring:
∴ </span><span>x² – 8x + 12 = (x-2)(x-6)

       </span><span>x² – x – 2 = (x-2)(x+1)

note: the factor (x-2) is common between them take it one time

∴ LCM = (x-2)(x-6)(x+1)
</span>
6 0
3 years ago
Read 2 more answers
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