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2 years ago

Find the sum of 3876, 9828 and 5030

Mathematics

2 answers:

Gnom [1K]2 years ago

7 0

3876+9828+5030= <u><em>18734</em></u>

Ne4ueva [31]2 years ago

5 0

Answer:

18,734

Step-by-step explanation:

just add them all

3876

9828

+ 5030

---------

18,734

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Help?!!?? I don’t get it??

solong [7]

Answer:

1/6

Step-by-step explanation:

1/2 (The probability that its tails) x 1/3(The probability that it lands on a green side)

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3 years ago

What is 2/4 as a decimal and percent

galben [10]

.5 as a decimal and 50% as a percent

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3 years ago

Read 2 more answers

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

A cone is placed inside a cylinder, as shown below. They have the same height and diameter. About how much space is inside the c

nadezda [96]

The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.

We know the volume of the cylinder is given:

$\rm V = \pi r^2 h$

r = 10/2 = 5 FT

h = 12 FT

$\rm V = \pi (5)^2 \times 12$

V = 300π cubic FT

Volume of the cone:

$\rm v = \dfrac{\pi r^2 h}{3}$

$\rm v = \dfrac{\pi (5)^2 \times 12}{3}$

v = 100π cubic FT

Space is inside the cylinder but outside the cone = 300π - 100π

= 200π cubic FT

= 628.32 cubic FT

Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

Learn more about the cone here:

brainly.com/question/16394302

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2 years ago

What is the maximum amount of baggage that may be loaded aboard the airplane for the cg to remain within the moment envelope? we

Korvikt [17]

<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.

In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>

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3 years ago