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sergij07 [2.7K]
2 years ago
15

Find the sum of 3876, 9828 and 5030

Mathematics
2 answers:
Gnom [1K]2 years ago
7 0

3876+9828+5030= <u><em>18734</em></u>

Ne4ueva [31]2 years ago
5 0

Answer:

18,734

Step-by-step explanation:

just add them all

3876

9828

+ 5030

---------

18,734

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Answer:

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What is 2/4 as a decimal and percent
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.5 as a decimal and 50% as a percent
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Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

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\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

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\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

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Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

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6 0
2 years ago
A cone is placed inside a cylinder, as shown below. They have the same height and diameter. About how much space is inside the c
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The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

<h3>What is a cone?</h3>

It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.

We know the volume of the cylinder is given:

\rm V = \pi r^2 h

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\rm V = \pi (5)^2 \times 12

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\rm v = \dfrac{\pi r^2 h}{3}

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Space is inside the cylinder but outside the cone = 300π - 100π

= 200π cubic FT

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Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

Learn more about the cone here:

brainly.com/question/16394302

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<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.

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