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Umnica [9.8K]
4 years ago
12

Solve each variable. Then match each equation with its correct answer. х -7 -15 = b - 18 4=n-2 b-(-16) = 17​

Mathematics
1 answer:
snow_tiger [21]4 years ago
3 0

Answer:

PLEASE READ EXPLANATION

1. x = 7

2. b = 3

3. n = 6

4. b = 1

Step-by-step explanation:

I’m going to assume the equations are as following - you made it a bit hard to read.

x - 7 = 0

-15 = b - 18

4 = n-2

b-(-16) = 17

I’m just shooting guesses here, if I said an equation wrong PLEASE let me know.

We can solve each equation by isolating x on one side.

Number 1:

x - 7 = 0\\\\x - 7 + 7 = 0 + 7\\\\x = 7

Number 2:

-15 = b - 18\\\\-15 + 18 = b - 18 + 18\\\\3 = b

Number 3:

4 = n-2\\\\4 + 2 = n - 2 + 2\\\\n = 6

Number 4:

b-(-16) = 17\\\\b+16=17\\\\b + 16 - 16 = 17 - 16\\\\b = 1

Hope this helped!

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Given the polynomial 21x^4+3y-6x^2+34 1. What polynomial must be subtracted from it to obtain 29x^2-7? 2. What polynomial must b
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Answer:

21x^4+3y-35x^2+41 must be subtracted

As you can see, we added -x+2 to this polynomial to obtain a first degree polynomial. (Though really anything with an x would do. For example, 3x, 2221x, or -224x would all work)

Step-by-step explanation:

We have the following polynomial

21x^4+3y-6x^2+34

And need to find a polynomial to subtract from it to get

29x^2-7

This means that if we subtract these two polynomials, we will get our desired polynomial

21x^4+3y-6x^2+34-(29x^2-7)\\\\21x^4+3y-6x^2+34-29x^2+7\\\\21x^4+3y-35x^2+41

Just to be sure, we can then check our work by finding the difference of the first polynomial and the one that we just found

21x^4+3y-6x^2+34-(21x^4+3y-35x^2+41)\\\\21x^4+3y-6x^2+34-21x^4-3y+35x^2-41\\\\-6x^2+34+35x^2-41\\\\29x^2-7

As we got the desired result, we know that this answer is correct.

And now for the second part of the problem. What polynomial must be added to it to obtain a first degree polynomial?

Recall that a first degree polynomial is one that has the total sum of 1. For example the polynomial x+5 is a first degree polynomial, but x+y+5 has a degree of 2.

This means that our desired polynomial needs to only have some amount of x's and constants.

We can do the same thing as the first time and simply subtract our desired result from the first polynomial. For simplicity, let us use the simple polynomial x+2

21x^4+3y-6x^2+34-(x-2)\\\\21x^4+3y-6x^2+34-x+2\\\\21x^4+3y-6x^2-x+36

As you can see, we added -x+2 to this polynomial to obtain a first degree polynomial. (Though really anything with an x would do. For example, 3x, 2221x, or -224x would all work)

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