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nika2105 [10]
3 years ago
10

NEED ASAP PLEASE

Mathematics
3 answers:
Vesna [10]3 years ago
7 1

Answer:

116.15

Step-by-step explanation:

1.95 - 30.00 - 7.20 - 38.50 = 38.50

77.65 = 38.50

x = $116.15

liberstina [14]3 years ago
4 1

Answer:

x - [1.95 + 30 + 7.20 + \frac{2}{3}{x - (1.95 + 30 + 7.20)}] = 38.5

Step-by-step explanation:

Let the total amount of money Liza has = $x.

Then, According to the question we get equation,

x - [1.95 + 30 + 7.20 + \frac{2}{3}{x - (1.95 + 30 + 7.20)}] = 38.5

⇒ x - [39.15 + \frac{2}{3}{x - 39.15}] = 38.5

⇒ x - 39.15 - \frac{2}{3}{x - 39.15} = 38.5

⇒ x - 39.15 = 3 × 38.5

⇒ x - 39.15 = 115.5

⇒ x = 154.65

Thus, she earned $154.65 by taking care of her neighbor's pet.

xxbtn2 years ago
0 0

1/3(m-1.95-30.0-7.20)=38.50
final answer:154.65

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Given f(x) = 4x3 − 12x2 + 40x + 12, find f(–2). A) f(–2) = –52 B) f(–2) = –96 C) f(–2) = –108 D) f(–2) = –148
AURORKA [14]

Given function : f(x) = 4x^3 -12x^2 + 40x + 12.

We need to find the values of f(-2).

In order to find the value of f(-2), we need to plug x=-2 in the given fucntion f(x) = 4x^3 -12x^2 + 40x + 12.

Replacing x by -2, we get

f(-2) = 4(-2)^3 -12(-2)^2 + 40(-2) + 12

We get (-2)^2 = -2 *-2*-2=-8 and (-2)^2 = -2 * -2 = 4.

f(-2) = 4(-8) -12(4) +40(-2) +12 .

f(-2) = -32 -48 -80+12.

f(-2) = -160 +12.

f(-2) = -148.

Therefore, correct option would be option D. That is  f(-2)=-148.                



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The question is telling you that the length of the rectangle is 3 metres more than twice the width.

So let:

<em>w= width</em>

<em>L= length</em>

Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>


They also tell you the perimeter is 48 metres.

<em>P= L+L+w+w</em>

So the equation of the perimeter is:

<em>48= (2w+3)+(2w+3)+2w +2w</em>

<em>48= 2(2w+3) + 4w</em>


To find w, expand and simplify.

<em>48= 4w+6+4w</em>

<em>48= 8w + 6</em>

<em>42= 8w</em>

<em>5.25=w</em>


Now that you know the width, plug in the value into the length equation:

<em>L= 2w+3</em>

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