Given:
Capacity of jet plane = 200,000 liters of fuel
Fuel used during flight = 130,000 liters
To find:
The percentage of the fuel capacity it uses on this flight.
Solution:
According to the question, we need to find 130,000 is what percent of 200,000.
![\text{Required percentage}=\dfrac{\text{Fuel used during flight}}{\text{Capacity of jet plane}}\times 100](https://tex.z-dn.net/?f=%5Ctext%7BRequired%20percentage%7D%3D%5Cdfrac%7B%5Ctext%7BFuel%20used%20during%20flight%7D%7D%7B%5Ctext%7BCapacity%20of%20jet%20plane%7D%7D%5Ctimes%20100)
![\text{Required percentage}=\dfrac{130000}{200000}\times 100](https://tex.z-dn.net/?f=%5Ctext%7BRequired%20percentage%7D%3D%5Cdfrac%7B130000%7D%7B200000%7D%5Ctimes%20100)
![\text{Required percentage}=65](https://tex.z-dn.net/?f=%5Ctext%7BRequired%20percentage%7D%3D65)
Therefore, the jet plane uses 65 percent of fuel capacity during flight.
Step-by-step explanation:
First we need to set up an equation so
12.50=4x+2.50
Simplify each side by subtracting the initial fee of 2.50
10=4x
divide by 4 to isolate x
2.5=x
You can park for 2.5 hours with your budget
V = 4/3(pi)(r^3)
V = 4/3(pi)(4.2^3)
V = 310 cm^3
Good luck!
Answer:12.57
Step-by-step explanation:
C=2πr
=2·π·2
=12.56637
Answer:
B) n ≥ -20
Step-by-step explanation:
n/4 ≥ -5
n ≥ -20