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pogonyaev
2 years ago
12

Pls help the first correct answer gets brainleist​

Mathematics
1 answer:
LenaWriter [7]2 years ago
4 0

Answer:

a=3 (i think)

Step-by-step explanation:

You might be interested in
How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and
omeli [17]

Step-by-step explanation:

x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\     (given)

Let us consider :

x_{1} = t_{1} + 1

x_{2} = t_{2}

x_{3} = t_{3}

x_{4}  = t_{4}

x_{5} = t_{5}

Now, by substituting the above considerations in the above equation, we get:

t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\

t_{1}  + t_{2} + t_{3} + t_{4} + t_{5} = 20\\

where,

t_{i} \geq 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = _{r}^{n + r}\textrm{C}

                                                      = _{4}^{24}\textrm{C}

                                                      = 10626

Answer :

no. of solutions for the eqn 10626

4 0
3 years ago
Is this correct ? check plsss...
d1i1m1o1n [39]
This looks one hundred percent correct to me and to check your answer you can plug in the answer you find to the first equation 


17=37+4f 
17=37+4(-5)
17=37-20
17=17 

great job!!
7 0
3 years ago
Read 2 more answers
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Guys i need your HELP ASAP​
ivanzaharov [21]
To solve this, you’ll first need to solve for their slopes.

The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3

We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3

The equation you get it y = 1/3x + b.

Now you will need to solve for b by substituting in the first ordered pair of line R.

2 = 1/3(1) + b.

Once you solve for b, you should get 5/3 and y = 1/3x + 5/3

Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.

y = 1/3(10) + 5/3.

Your solution should be 5.

So your answer is: a = 5
8 0
3 years ago
The width of Estelle's rectangular living room is 4 meters, and the distance between opposite corners is 7 meters. What is the l
Crank

Answer:

5.7 meters

Step-by-step explanation:

Image a rectangle being cut diagonally in half, that would lead to two triangles. We can use the pythagorean theorem to find the missing side.

7 is the hypotenuse and 4 is the side length

4^2+x^2=7^2

16+x^2=49

sqrx=sqr(49-16)

x=sqr33

x=5.74

Rounded to the nearest tenth is 5.7

6 0
3 years ago
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