Melisande collected 14 bottles on Saturday and 9 bottles on Sunday for recycling. On Monday, she took all the bottles to the rec
ycling center, where they paid her a certain amount, b, for each bottle. However, she had to pay the recycling center a one-time service fee of $0.25. If she left there with $3.20 for the bottles, what is the value of b?
2 answers:
You might be interested in
The length of hypotenuse is 39.
Step-by-step explanation:
Given,
Vertical side = a = 15
Horizontal side = b = 36
Hypotenuse = c
Using pythagorean theorem
Taking square root on both sides
The length of hypotenuse is 39.
Keywords: square root, addition
Learn more about square roots at:
#LearnwithBrainly
I hope this helps you
Answer:
a)
b)
c)
d)
e)
And we take the absolute value on the middle integral because the distance can't be negative.
f)
g) The particle is speeding up
And would be slowing down from
Step-by-step explanation:
For this case we have the following function given:
Part a: Find the velocity at time t.
For this case we just need to take the derivate of the position function respect to t like this:
Part b: What is the velocity after 3 s?
For this case we just need to replace t=3 s into the velocity equation and we got:
Part c: When is the particle at rest?
The particle would be at rest when the velocity would be 0 so we need to solve the following equation:
We can divide both sides of the equation by 3 and we got:
And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:
And for this case we got
Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)
For this case the particle is moving in the positive direction when the velocity is higher than 0:
So then the intervals positive are
Part e: Find the total distance traveled during the first 6 s.
We can calculate the total distance with the following integral:
And if we replace we got:
And we take the absolute value on the middle integral because the distance can't be negative.
Part f: Find the acceleration at time t.
For this case we ust need to take the derivate of the velocity respect to the time like this:
Part g and h
The particle is speeding up
And would be slowing down from