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3 years ago

1. Which expression represents the following calculation?"Add 4 and 6, then multiply 5,then add 10.

Mathematics

1 answer:

il63 [147K]3 years ago

4 0

Answer:

1. 5(4 + 6) + 1-0

2. 9(9b + 2)

3. 40

4. Nine plus r multiplied by four over five and then added to eight w.

5. The quotient is $\frac{45}{d}$

Step-by-step explanation:

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Toys-A-Go makes toys at Plant A and Plant B. Plant A needs to make a minimum of 1000 toy dump trucks and fire engines. Plant B n

Citrus2011 [14]

Answer:

88 hours on dump truck

24 hours on fire engine

Minimum cost is $3480

Step-by-step explanation:

D > 0; f >0

Plant A : 10d+5f >100

Plant B: 5d +15f >800

Cost:

C(x,y)+30D+35F

4 0

3 years ago

Read 2 more answers

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

3 years ago

Multiply what is 109-91

xenn [34]

109-91 is 18, but multiplied is 9919

3 0

3 years ago

Read 2 more answers

Celia uses the steps below to solve the equation Negative StartFraction 3 over 8 EndFraction (negative 8 minus 16 d) + 2 d = 24.

Troyanec [42]

The error in the steps is that In step 1, she should have also distributed -3/8 over –16d, to get 3 + 6 d + 2 d = 24

<h3>Simplifying linear equations</h3>

Given the following equation as shown below

-3/8(-8-16d)+2d = 24

Step 1 Distribute -3/8 over the expression in parentheses

3 + 6d + 2d = 24

Simply the like terms

3 + 8d = 24

Subtract 3 from both sides of the equation.

8d = 24 - 3

8d = 21

d = 21/8

Hence the error in the steps is that In step 1, she should have also distributed -3/8 over –16d, to get 3 + 6 d + 2 d = 24

Learn more on linear equation here: brainly.com/question/1884491

#SPJ1

3 0

2 years ago

1. Identify the focus and the directrix for 36(y+9) = (x - 5)^2 2. Identify the focus and the directrix for 20(x-8) = (y + 3)^2

Simora [160]

Problem 1

Focus: (5, 0)

Directrix: y = -18

------------------

Explanation:

The given equation can be written as 4*9(y-(-9)) = (x-5)^2

Then compare this to the form 4p(y-k) = (x-h)^2

We see that p = 9. This is the focal distance. It is the distance from the vertex to the focus along the axis of symmetry. The vertex here is (h,k) = (5,-9)

We'll start at the vertex (5,-9) and move upward 9 units to get to (5,0) which is where the focus is situated. Why did we move up? Because the original equation can be written into the form y = a(x-h)^2 + k, and it turns out that a = 1/36 in this case, which is a positive value. When 'a' is positive, the focus is above the vertex (to allow the parabola to open upward)

The directrix is the horizontal line perpendicular to the axis of symmetry. We will start at (5,-9) and move 9 units down (opposite direction as before) to arrive at y = -18 as the directrix. Note how the point (5,-18) is on this horizontal line.

================================================

Problem 2

Focus: (13,-3)

Directrix: x = 3

------------------

Explanation:

We'll use a similar idea as in problem 1. However, this time the parabola opens to the right (rather than up) because we are squaring the y term this time.

20(x-8) = (y+3)^2 is the same as 4*5(x-8) = (y-(-3))^2

It is in the form 4p(x-h) = (y-k)^2

vertex = (h,k) = (8,-3)

focal length = p = 5

Start at the vertex and move 5 units to the right to arrive at (13,-3). This is the location of the focus.

Go back to the focus and move 5 units to the left to arrive at (3,-3). Then draw a vertical line through this point to generate the directrix line x = 3

5 0

3 years ago